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9x^2-600x-50000=0
a = 9; b = -600; c = -50000;
Δ = b2-4ac
Δ = -6002-4·9·(-50000)
Δ = 2160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2160000}=\sqrt{360000*6}=\sqrt{360000}*\sqrt{6}=600\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-600\sqrt{6}}{2*9}=\frac{600-600\sqrt{6}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+600\sqrt{6}}{2*9}=\frac{600+600\sqrt{6}}{18} $
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